What are the solutions to the equation 0.3q^2+q-40=0 ?

The solutions to the equation 0.3q^2+q-40=0 are q=10,q=-40/3

Find the zeros of 0.3q^2+q-40=0

The zeros of 0.3q^2+q-40=0 are q=10,q=-40/3

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0.3 q^{2} + q - 40 = 0

q = 10, q = - \frac{40}{3}

Decimal Notation

q = 10, q = - 13.33333 \dots

Solution steps

0.3 q^{2} + q - 40 = 0

Multiply both sides by

10

3 q^{2} + 10 q - 400 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 400 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 400) = 70

q_{1, 2} = \frac{- 10 \pm 70}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- 10 + 70}{2 \cdot 3}, q_{2} = \frac{- 10 - 70}{2 \cdot 3}

q = \frac{- 10 + 70}{2 \cdot 3} : 10

q = \frac{- 10 - 70}{2 \cdot 3} : - \frac{40}{3}

The solutions to the quadratic equation are:

q = 10, q = - \frac{40}{3}

4 d^{2} + 9 d - 7 = 22

- x^{2} + 10 x

x, y^{2} - x y + x^{2} = 8

(x - 3)^{2} = 9 x

- 6 x^{2} + 4 x + 5 = 0

What are the solutions to the equation 0.3q^2+q-40=0 ?
The solutions to the equation 0.3q^2+q-40=0 are q=10,q=-40/3
Find the zeros of 0.3q^2+q-40=0
The zeros of 0.3q^2+q-40=0 are q=10,q=-40/3