What are the solutions to the equation 2^2+sqrt(-1)+x^2=2 ?

The solutions to the equation 2^2+sqrt(-1)+x^2=2 are

Find the zeros of 2^2+sqrt(-1)+x^2=2

The zeros of 2^2+sqrt(-1)+x^2=2 are

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2^{2} + - 1 + x^{2} = 2

Solution steps

2^{2} + - 1 + x^{2} = 2

Move

- 1

to the right side

2^{2} + x^{2} = 2 - i

Move

2^{2}

to the right side

x^{2} = - 2 - i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 2, a = - 2 - i

∣ a ∣ = 5

ar g (a) = arctan (\frac{1}{2}) - π

x = 5 (cos (\frac{arctan ( \frac{1}{2} ) - π + 2 \cdot 0 π}{2}) + i sin (\frac{arctan ( \frac{1}{2} ) - π + 2 \cdot 0 π}{2})), x = 5 (cos (\frac{arctan ( \frac{1}{2} ) - π + 2 \cdot 1 π}{2}) + i sin (\frac{arctan ( \frac{1}{2} ) - π + 2 \cdot 1 π}{2}))

Simplify

125 x^{2} + 20 = 0

x, 9 x^{2} + 16 y^{2} = 0

l (q) = 5 q^{2} - 8 q + 12

t, d t + 0.5 t = d t (0.5 t)

(7 - h)^{2} + (3 - k)^{2} = r^{2}

What are the solutions to the equation 2^2+sqrt(-1)+x^2=2 ?
The solutions to the equation 2^2+sqrt(-1)+x^2=2 are
Find the zeros of 2^2+sqrt(-1)+x^2=2
The zeros of 2^2+sqrt(-1)+x^2=2 are