What are the solutions to the equation 8x^2+6x-34=0 ?

The solutions to the equation 8x^2+6x-34=0 are x=(-3+sqrt(281))/8 ,x=-(3+sqrt(281))/8

Find the zeros of 8x^2+6x-34=0

The zeros of 8x^2+6x-34=0 are x=(-3+sqrt(281))/8 ,x=-(3+sqrt(281))/8

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8 x^{2} + 6 x - 34 = 0

x = \frac{- 3 + 281}{8}, x = - \frac{3 + 281}{8}

Decimal Notation

x = 1.72038 \dots, x = - 2.47038 \dots

Solution steps

8 x^{2} + 6 x - 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 8 ( - 34 )}{2 \cdot 8}

6^{2} - 4 \cdot 8 (- 34) = 2281

x_{1, 2} = \frac{- 6 \pm 2 281}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 6 + 2 281}{2 \cdot 8}, x_{2} = \frac{- 6 - 2 281}{2 \cdot 8}

x = \frac{- 6 + 2 281}{2 \cdot 8} : \frac{- 3 + 281}{8}

x = \frac{- 6 - 2 281}{2 \cdot 8} : - \frac{3 + 281}{8}

The solutions to the quadratic equation are:

x = \frac{- 3 + 281}{8}, x = - \frac{3 + 281}{8}

x^{2} + 2000 x = 2001

96 = 2 y^{2}

9 x^{2} + 3 x = - 2 x

(9.81) (280) + \frac{1}{2} (5)^{2} = \frac{1}{2} x^{2}

(y - 1)^{2} = 1

What are the solutions to the equation 8x^2+6x-34=0 ?
The solutions to the equation 8x^2+6x-34=0 are x=(-3+sqrt(281))/8 ,x=-(3+sqrt(281))/8
Find the zeros of 8x^2+6x-34=0
The zeros of 8x^2+6x-34=0 are x=(-3+sqrt(281))/8 ,x=-(3+sqrt(281))/8