What are the solutions to the equation x^2+17x-2=0 ?

The solutions to the equation x^2+17x-2=0 are x=(-17+3sqrt(33))/2 ,x=(-17-3sqrt(33))/2

Find the zeros of x^2+17x-2=0

The zeros of x^2+17x-2=0 are x=(-17+3sqrt(33))/2 ,x=(-17-3sqrt(33))/2

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x^{2} + 17 x - 2 = 0

x = \frac{- 17 + 3 33}{2}, x = \frac{- 17 - 3 33}{2}

Decimal Notation

x = 0.11684 \dots, x = - 17.11684 \dots

Solution steps

x^{2} + 17 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot (- 2) = 333

x_{1, 2} = \frac{- 17 \pm 3 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 3 33}{2 \cdot 1}, x_{2} = \frac{- 17 - 3 33}{2 \cdot 1}

x = \frac{- 17 + 3 33}{2 \cdot 1} : \frac{- 17 + 3 33}{2}

x = \frac{- 17 - 3 33}{2 \cdot 1} : \frac{- 17 - 3 33}{2}

The solutions to the quadratic equation are:

x = \frac{- 17 + 3 33}{2}, x = \frac{- 17 - 3 33}{2}

x^{2} + \frac{1}{3} x + 1 = 0

a^{2} = 9 + 16

p^{2} + 42 = 13 p

150 = 200 - 20 t + 2 t^{2}

m^{2} - 6 m = 7

What are the solutions to the equation x^2+17x-2=0 ?
The solutions to the equation x^2+17x-2=0 are x=(-17+3sqrt(33))/2 ,x=(-17-3sqrt(33))/2
Find the zeros of x^2+17x-2=0
The zeros of x^2+17x-2=0 are x=(-17+3sqrt(33))/2 ,x=(-17-3sqrt(33))/2