What are the solutions to the equation 1=(x^2)/4 ?

The solutions to the equation 1=(x^2)/4 are x=2,x=-2

Find the zeros of 1=(x^2)/4

The zeros of 1=(x^2)/4 are x=2,x=-2

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1 = \frac{x ^{2}}{4}

x = 2, x = - 2

Solution steps

1 = \frac{x ^{2}}{4}

Switch sides

\frac{x ^{2}}{4} = 1

Multiply both sides by

4

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x^{2} + 20 x + 28 = 9

6 x^{2} + 17 x + 7 = 0

2 0^{2} + 2 0^{2} = x^{2}

y^{2} - 12 y - 64 = 0

13 x^{2} - 156 x + 468 = 0

What are the solutions to the equation 1=(x^2)/4 ?
The solutions to the equation 1=(x^2)/4 are x=2,x=-2
Find the zeros of 1=(x^2)/4
The zeros of 1=(x^2)/4 are x=2,x=-2