What are the solutions to the equation 2=-x^2 ?

The solutions to the equation 2=-x^2 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of 2=-x^2

The zeros of 2=-x^2 are x=sqrt(2)i,x=-sqrt(2)i

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2 = - x^{2}

x = 2 i, x = - 2 i

Solution steps

2 = - x^{2}

Switch sides

- x^{2} = 2

Divide both sides by

- 1

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

a, f (a + 7) = (a + 7)^{2} + 1

5 x^{2} - 10 x - 75 = 0

s^{2} + 6 s + 36.9 = 0

- 2 x^{2} + 3 x - 1

- p^{2} + 2 p + 3 = 0

What are the solutions to the equation 2=-x^2 ?
The solutions to the equation 2=-x^2 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of 2=-x^2
The zeros of 2=-x^2 are x=sqrt(2)i,x=-sqrt(2)i