What are the solutions to the equation 0.25=-0.5x^2+x ?

The solutions to the equation 0.25=-0.5x^2+x are x=(2-sqrt(2))/2 ,x=(2+sqrt(2))/2

Find the zeros of 0.25=-0.5x^2+x

The zeros of 0.25=-0.5x^2+x are x=(2-sqrt(2))/2 ,x=(2+sqrt(2))/2

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0.25 = - 0.5 x^{2} + x

x = \frac{2 - 2}{2}, x = \frac{2 + 2}{2}

Decimal Notation

x = 0.29289 \dots, x = 1.70710 \dots

Solution steps

0.25 = - 0.5 x^{2} + x

Multiply both sides by

100

25 = - 50 x^{2} + 100 x

Switch sides

- 50 x^{2} + 100 x = 25

Move

25

to the left side

- 50 x^{2} + 100 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 50 ) ( - 25 )}{2 ( - 50 )}

10 0^{2} - 4 (- 50) (- 25) = 502

x_{1, 2} = \frac{- 100 \pm 50 2}{2 ( - 50 )}

Separate the solutions

x_{1} = \frac{- 100 + 50 2}{2 ( - 50 )}, x_{2} = \frac{- 100 - 50 2}{2 ( - 50 )}

x = \frac{- 100 + 50 2}{2 ( - 50 )} : \frac{2 - 2}{2}

x = \frac{- 100 - 50 2}{2 ( - 50 )} : \frac{2 + 2}{2}

The solutions to the quadratic equation are:

x = \frac{2 - 2}{2}, x = \frac{2 + 2}{2}

7^{2} + 1^{2} = c^{2}

X \cdot (1 - 0.59 \cdot X) = 0.14462

(- x - 4) (4 x - 2 + 3) = - (6 x - 8) + (2 x - 4 + 3)

x, (x - 7)^{2} + y^{2} = r^{2}

(x - 1) (x - \frac{1}{2}) = 0

What are the solutions to the equation 0.25=-0.5x^2+x ?
The solutions to the equation 0.25=-0.5x^2+x are x=(2-sqrt(2))/2 ,x=(2+sqrt(2))/2
Find the zeros of 0.25=-0.5x^2+x
The zeros of 0.25=-0.5x^2+x are x=(2-sqrt(2))/2 ,x=(2+sqrt(2))/2