What are the solutions to the equation 1/2 x^2+5x=-17 ?

The solutions to the equation 1/2 x^2+5x=-17 are x=-5+3i,x=-5-3i

Find the zeros of 1/2 x^2+5x=-17

The zeros of 1/2 x^2+5x=-17 are x=-5+3i,x=-5-3i

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\frac{1}{2} x^{2} + 5 x = - 17

x = - 5 + 3 i, x = - 5 - 3 i

Solution steps

\frac{1}{2} x^{2} + 5 x = - 17

Multiply both sides by

2

x^{2} + 10 x = - 34

Move

34

to the left side

x^{2} + 10 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 34 : 6 i

x_{1, 2} = \frac{- 10 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 6 i}{2 \cdot 1}

x = \frac{- 10 + 6 i}{2 \cdot 1} : - 5 + 3 i

x = \frac{- 10 - 6 i}{2 \cdot 1} : - 5 - 3 i

The solutions to the quadratic equation are:

x = - 5 + 3 i, x = - 5 - 3 i

y^{2} - 9 y - 18 = 0

x^{2} - 83 x + 169 = 0

40 = \frac{( 0.0826 ) ( 0.015 ) ( 200 ) ( x ) ^{2}}{( 0.1 ) ^{5}}

X^{2} - 4 = 32

x, ln (y) = \frac{x ^{2}}{2} + c

What are the solutions to the equation 1/2 x^2+5x=-17 ?
The solutions to the equation 1/2 x^2+5x=-17 are x=-5+3i,x=-5-3i
Find the zeros of 1/2 x^2+5x=-17
The zeros of 1/2 x^2+5x=-17 are x=-5+3i,x=-5-3i