What are the solutions to the equation 10x^2-33x+20=0 ?

The solutions to the equation 10x^2-33x+20=0 are x= 5/2 ,x= 4/5

Find the zeros of 10x^2-33x+20=0

The zeros of 10x^2-33x+20=0 are x= 5/2 ,x= 4/5

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10 x^{2} - 33 x + 20 = 0

x = \frac{5}{2}, x = \frac{4}{5}

Decimal Notation

x = 2.5, x = 0.8

Solution steps

10 x^{2} - 33 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 33 ) \pm ( - 33 ) ^{2} - 4 \cdot 10 \cdot 20}{2 \cdot 10}

(- 33)^{2} - 4 \cdot 10 \cdot 20 = 17

x_{1, 2} = \frac{- ( - 33 ) \pm 17}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 33 ) + 17}{2 \cdot 10}, x_{2} = \frac{- ( - 33 ) - 17}{2 \cdot 10}

x = \frac{- ( - 33 ) + 17}{2 \cdot 10} : \frac{5}{2}

x = \frac{- ( - 33 ) - 17}{2 \cdot 10} : \frac{4}{5}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{4}{5}

4 x^{2} - 36 x + 81

1.36 x^{2} + 27.8 x + 304 = 500

(400 + j^{1000}) I^{2} - j^{90} I^{1} = 0

49 x^{2} - 60 = 0

x^{2} + 15 = 8

What are the solutions to the equation 10x^2-33x+20=0 ?
The solutions to the equation 10x^2-33x+20=0 are x= 5/2 ,x= 4/5
Find the zeros of 10x^2-33x+20=0
The zeros of 10x^2-33x+20=0 are x= 5/2 ,x= 4/5