What are the solutions to the equation 3x^2+10x=-9 ?

The solutions to the equation 3x^2+10x=-9 are x=-5/3+i(sqrt(2))/3 ,x=-5/3-i(sqrt(2))/3

Find the zeros of 3x^2+10x=-9

The zeros of 3x^2+10x=-9 are x=-5/3+i(sqrt(2))/3 ,x=-5/3-i(sqrt(2))/3

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3 x^{2} + 10 x = - 9

x = - \frac{5}{3} + i \frac{2}{3}, x = - \frac{5}{3} - i \frac{2}{3}

Solution steps

3 x^{2} + 10 x = - 9

Move

9

to the left side

3 x^{2} + 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

1 0^{2} - 4 \cdot 3 \cdot 9 : 22 i

x_{1, 2} = \frac{- 10 \pm 2 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 2 2 i}{2 \cdot 3}, x_{2} = \frac{- 10 - 2 2 i}{2 \cdot 3}

x = \frac{- 10 + 2 2 i}{2 \cdot 3} : - \frac{5}{3} + i \frac{2}{3}

x = \frac{- 10 - 2 2 i}{2 \cdot 3} : - \frac{5}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{5}{3} + i \frac{2}{3}, x = - \frac{5}{3} - i \frac{2}{3}

8 x - x^{2} = 16

x^{2} + 3 x = 88

18 = 6 + 29 t - 16 t^{2}

3 x^{2} - 9 x - 4 = 0

x^{2} = 5^{2} + 2^{2}

What are the solutions to the equation 3x^2+10x=-9 ?
The solutions to the equation 3x^2+10x=-9 are x=-5/3+i(sqrt(2))/3 ,x=-5/3-i(sqrt(2))/3
Find the zeros of 3x^2+10x=-9
The zeros of 3x^2+10x=-9 are x=-5/3+i(sqrt(2))/3 ,x=-5/3-i(sqrt(2))/3