What are the solutions to the equation -x^{(2)}-x+6=0 ?

The solutions to the equation -x^{(2)}-x+6=0 are x=-3,x=2

Find the zeros of -x^{(2)}-x+6=0

The zeros of -x^{(2)}-x+6=0 are x=-3,x=2

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- x^{(2)} - x + 6 = 0

x = - 3, x = 2

Solution steps

- x^{(2)} - x + 6 = 0

Refine

- x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 6 = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 5}{2 ( - 1 )} : - 3

x = \frac{- ( - 1 ) - 5}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 3, x = 2

4 = \frac{2}{5} x^{2} + \frac{2}{5} x - 5

490 = - 250 t^{2} + 700 t

x, x^{2} + 2 x + 7 = 0

x, 2 x^{2} + 12 k x - 16 = 0

z i n^{2} z + 7 = 79

What are the solutions to the equation -x^{(2)}-x+6=0 ?
The solutions to the equation -x^{(2)}-x+6=0 are x=-3,x=2
Find the zeros of -x^{(2)}-x+6=0
The zeros of -x^{(2)}-x+6=0 are x=-3,x=2