What are the solutions to the equation -2x^2-4x+2=0 ?

The solutions to the equation -2x^2-4x+2=0 are x=-1-sqrt(2),x=sqrt(2)-1

Find the zeros of -2x^2-4x+2=0

The zeros of -2x^2-4x+2=0 are x=-1-sqrt(2),x=sqrt(2)-1

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- 2 x^{2} - 4 x + 2 = 0

x = - 1 - 2, x = 2 - 1

Decimal Notation

x = - 2.41421 \dots, x = 0.41421 \dots

Solution steps

- 2 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) \cdot 2}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) \cdot 2 = 42

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 4 2}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 4 2}{2 ( - 2 )} : - 1 - 2

x = \frac{- ( - 4 ) - 4 2}{2 ( - 2 )} : 2 - 1

The solutions to the quadratic equation are:

x = - 1 - 2, x = 2 - 1

0 = x^{2} + 3 x + 6

0 = x^{2} + 3 x + 4

y^{2} - 14 y + 40 = 0

(1 - x)^{2} = \frac{9}{25}

x^{2} + 7 x = 0

What are the solutions to the equation -2x^2-4x+2=0 ?
The solutions to the equation -2x^2-4x+2=0 are x=-1-sqrt(2),x=sqrt(2)-1
Find the zeros of -2x^2-4x+2=0
The zeros of -2x^2-4x+2=0 are x=-1-sqrt(2),x=sqrt(2)-1