What are the solutions to the equation 3(6x-5)-(6x-5)^2=0 ?

The solutions to the equation 3(6x-5)-(6x-5)^2=0 are x= 5/6 ,x= 4/3

Find the zeros of 3(6x-5)-(6x-5)^2=0

The zeros of 3(6x-5)-(6x-5)^2=0 are x= 5/6 ,x= 4/3

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3 (6 x - 5) - (6 x - 5)^{2} = 0

x = \frac{5}{6}, x = \frac{4}{3}

Decimal Notation

x = 0.83333 \dots, x = 1.33333 \dots

Solution steps

3 (6 x - 5) - (6 x - 5)^{2} = 0

Expand

3 (6 x - 5) - (6 x - 5)^{2} : - 36 x^{2} + 78 x - 40

- 36 x^{2} + 78 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 78 \pm 7 8 ^{2} - 4 ( - 36 ) ( - 40 )}{2 ( - 36 )}

7 8^{2} - 4 (- 36) (- 40) = 18

x_{1, 2} = \frac{- 78 \pm 18}{2 ( - 36 )}

Separate the solutions

x_{1} = \frac{- 78 + 18}{2 ( - 36 )}, x_{2} = \frac{- 78 - 18}{2 ( - 36 )}

x = \frac{- 78 + 18}{2 ( - 36 )} : \frac{5}{6}

x = \frac{- 78 - 18}{2 ( - 36 )} : \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = \frac{4}{3}

3 (x + 8)^{2} - 12 = 24

7 x^{2} - 18 x + 12 = 0

x - 2 x^{2} = 0

10 x^{2} + 30 x - 500 = 0

4 x^{2} + 16 x - 8 = 0

What are the solutions to the equation 3(6x-5)-(6x-5)^2=0 ?
The solutions to the equation 3(6x-5)-(6x-5)^2=0 are x= 5/6 ,x= 4/3
Find the zeros of 3(6x-5)-(6x-5)^2=0
The zeros of 3(6x-5)-(6x-5)^2=0 are x= 5/6 ,x= 4/3