What are the solutions to the equation solvefor x,x^2+2x+9=0 ?

The solutions to the equation solvefor x,x^2+2x+9=0 are x=-1+2sqrt(2)i,x=-1-2sqrt(2)i

Find the zeros of solvefor x,x^2+2x+9=0

The zeros of solvefor x,x^2+2x+9=0 are x=-1+2sqrt(2)i,x=-1-2sqrt(2)i

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x, x^{2} + 2 x + 9 = 0

x = - 1 + 22 i, x = - 1 - 22 i

Solution steps

x^{2} + 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 9 : 42 i

x_{1, 2} = \frac{- 2 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 2 i}{2 \cdot 1}

x = \frac{- 2 + 4 2 i}{2 \cdot 1} : - 1 + 22 i

x = \frac{- 2 - 4 2 i}{2 \cdot 1} : - 1 - 22 i

The solutions to the quadratic equation are:

x = - 1 + 22 i, x = - 1 - 22 i

15 = 18 x^{2} + 15 x - 10

x (3 x - 4) = 5

6 a^{2} - 24 a = - 18

k, x^{3} - k^{2} x^{2} - 8 k x - 16 = 0

x, x^{2} y + x y^{2} + x^{2} - y^{2} + x y - 2 y - 4 = 0

What are the solutions to the equation solvefor x,x^2+2x+9=0 ?
The solutions to the equation solvefor x,x^2+2x+9=0 are x=-1+2sqrt(2)i,x=-1-2sqrt(2)i
Find the zeros of solvefor x,x^2+2x+9=0
The zeros of solvefor x,x^2+2x+9=0 are x=-1+2sqrt(2)i,x=-1-2sqrt(2)i