What are the solutions to the equation 2x^2-2sqrt(2)x+1=0 ?

The solutions to the equation 2x^2-2sqrt(2)x+1=0 are x=0.70710…

Find the zeros of 2x^2-2sqrt(2)x+1=0

The zeros of 2x^2-2sqrt(2)x+1=0 are x=0.70710…

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2 x^{2} - 22 x + 1 = 0

x = 0.70710 \dots

Solution steps

2 x^{2} - 22 x + 1 = 0

Factor

2 x^{2} - 22 x + 1 : (1.41421 \dots x - 1)^{2}

(1.41421 \dots x - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1.41421 \dots x - 1 = 0

Solve

1.41421 \dots x - 1 = 0 : x = 0.70710 \dots

The solution to the quadratic equation is:

x = 0.70710 \dots

36 t - 0.8 t^{2} = 0

x (x - 3) - (x - 7) = 28

4 x^{2} = 21 x + 8

(5 m - 3)^{2} + 30 m = 0

0 + 3.2 - 1.6 = 5 u^{2}

What are the solutions to the equation 2x^2-2sqrt(2)x+1=0 ?
The solutions to the equation 2x^2-2sqrt(2)x+1=0 are x=0.70710…
Find the zeros of 2x^2-2sqrt(2)x+1=0
The zeros of 2x^2-2sqrt(2)x+1=0 are x=0.70710…