What are the solutions to the equation w^2-16w+46=-117 ?

The solutions to the equation w^2-16w+46=-117 are w=8+3sqrt(11)i,w=8-3sqrt(11)i

Find the zeros of w^2-16w+46=-117

The zeros of w^2-16w+46=-117 are w=8+3sqrt(11)i,w=8-3sqrt(11)i

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w^{2} - 16 w + 46 = - 117

w = 8 + 311 i, w = 8 - 311 i

Solution steps

w^{2} - 16 w + 46 = - 117

Move

117

to the left side

w^{2} - 16 w + 163 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 163}{2 \cdot 1}

Simplify

(- 16)^{2} - 4 \cdot 1 \cdot 163 : 611 i

w_{1, 2} = \frac{- ( - 16 ) \pm 6 11 i}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 16 ) + 6 11 i}{2 \cdot 1}, w_{2} = \frac{- ( - 16 ) - 6 11 i}{2 \cdot 1}

w = \frac{- ( - 16 ) + 6 11 i}{2 \cdot 1} : 8 + 311 i

w = \frac{- ( - 16 ) - 6 11 i}{2 \cdot 1} : 8 - 311 i

The solutions to the quadratic equation are:

w = 8 + 311 i, w = 8 - 311 i

v^{2} + 10 v - 2000 = 0

f (7) = - x^{2} - 8, x \geq 5

11 x - x^{2} = 10

12 x^{2} + 8 x = 7

(x + a) (x - a) + 4 a (a - x) = 0

What are the solutions to the equation w^2-16w+46=-117 ?
The solutions to the equation w^2-16w+46=-117 are w=8+3sqrt(11)i,w=8-3sqrt(11)i
Find the zeros of w^2-16w+46=-117
The zeros of w^2-16w+46=-117 are w=8+3sqrt(11)i,w=8-3sqrt(11)i