What are the solutions to the equation x^2-3x=-20 ?

The solutions to the equation x^2-3x=-20 are x= 3/2+i(sqrt(71))/2 ,x= 3/2-i(sqrt(71))/2

Find the zeros of x^2-3x=-20

The zeros of x^2-3x=-20 are x= 3/2+i(sqrt(71))/2 ,x= 3/2-i(sqrt(71))/2

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x^{2} - 3 x = - 20

x = \frac{3}{2} + i \frac{71}{2}, x = \frac{3}{2} - i \frac{71}{2}

Solution steps

x^{2} - 3 x = - 20

Move

20

to the left side

x^{2} - 3 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 20 : 71 i

x_{1, 2} = \frac{- ( - 3 ) \pm 71 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 71 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 71 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 71 i}{2 \cdot 1} : \frac{3}{2} + i \frac{71}{2}

x = \frac{- ( - 3 ) - 71 i}{2 \cdot 1} : \frac{3}{2} - i \frac{71}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{71}{2}, x = \frac{3}{2} - i \frac{71}{2}

1 0^{2} = 8^{2} + b^{2}

x^{2} + 5 x + 150 = 0

2 x^{2} + 12 x - 7

x, 4 x^{2} + y^{2} + z^{2} - 24 x - 8 y + 4 z + 55 = 0

y^{2} + 6 y = - 1

What are the solutions to the equation x^2-3x=-20 ?
The solutions to the equation x^2-3x=-20 are x= 3/2+i(sqrt(71))/2 ,x= 3/2-i(sqrt(71))/2
Find the zeros of x^2-3x=-20
The zeros of x^2-3x=-20 are x= 3/2+i(sqrt(71))/2 ,x= 3/2-i(sqrt(71))/2