What are the solutions to the equation x^2-10x-48=0 ?

The solutions to the equation x^2-10x-48=0 are x=5+sqrt(73),x=5-sqrt(73)

Find the zeros of x^2-10x-48=0

The zeros of x^2-10x-48=0 are x=5+sqrt(73),x=5-sqrt(73)

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x^{2} - 10 x - 48 = 0

x = 5 + 73, x = 5 - 73

Decimal Notation

x = 13.54400 \dots, x = - 3.54400 \dots

Solution steps

x^{2} - 10 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 48) = 273

x_{1, 2} = \frac{- ( - 10 ) \pm 2 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 73}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 73}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 73}{2 \cdot 1} : 5 + 73

x = \frac{- ( - 10 ) - 2 73}{2 \cdot 1} : 5 - 73

The solutions to the quadratic equation are:

x = 5 + 73, x = 5 - 73

28 = 28 T^{2} - 179 T + 89

0 = 144 - 16 t^{2}

0.002 s^{2} + 0.02 s + 1 = 0

x^{2} + 4 x + 4 = 4

- \frac{1}{4} f^{2} + \frac{5}{4} f + \frac{15}{4} = 0

What are the solutions to the equation x^2-10x-48=0 ?
The solutions to the equation x^2-10x-48=0 are x=5+sqrt(73),x=5-sqrt(73)
Find the zeros of x^2-10x-48=0
The zeros of x^2-10x-48=0 are x=5+sqrt(73),x=5-sqrt(73)