What are the solutions to the equation y^2+17y+16=0 ?

The solutions to the equation y^2+17y+16=0 are y=-1,y=-16

Find the zeros of y^2+17y+16=0

The zeros of y^2+17y+16=0 are y=-1,y=-16

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y^{2} + 17 y + 16 = 0

y = - 1, y = - 16

Solution steps

y^{2} + 17 y + 16 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 16 = 15

y_{1, 2} = \frac{- 17 \pm 15}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 17 + 15}{2 \cdot 1}, y_{2} = \frac{- 17 - 15}{2 \cdot 1}

y = \frac{- 17 + 15}{2 \cdot 1} : - 1

y = \frac{- 17 - 15}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

y = - 1, y = - 16

x^{2} + 2 x + 50

\frac{6 ^{2}}{1 5 ^{2}} + \frac{x ^{2}}{1 0 ^{2}} = 1

104.607075 = 0.1775 x^{2} - 36.621 x + 2005.1

7 r^{2} + 9 = - 81

2 x^{2} + 2 x + 18 = 0

What are the solutions to the equation y^2+17y+16=0 ?
The solutions to the equation y^2+17y+16=0 are y=-1,y=-16
Find the zeros of y^2+17y+16=0
The zeros of y^2+17y+16=0 are y=-1,y=-16