What are the solutions to the equation ((3x)^2+(4x)^2)-4x+975x=5x^2 ?

The solutions to the equation ((3x)^2+(4x)^2)-4x+975x=5x^2 are x=0,x=-971/20

Find the zeros of ((3x)^2+(4x)^2)-4x+975x=5x^2

The zeros of ((3x)^2+(4x)^2)-4x+975x=5x^2 are x=0,x=-971/20

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((3 x)^{2} + (4 x)^{2}) - 4 x + 975 x = 5 x^{2}

x = 0, x = - \frac{971}{20}

Decimal Notation

x = 0, x = - 48.55

Solution steps

((3 x)^{2} + (4 x)^{2}) - 4 x + 975 x = 5 x^{2}

Expand

((3 x)^{2} + (4 x)^{2}) - 4 x + 975 x : 25 x^{2} + 971 x

25 x^{2} + 971 x = 5 x^{2}

Move

5 x^{2}

to the left side

20 x^{2} + 971 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 971 \pm 97 1 ^{2} - 4 \cdot 20 \cdot 0}{2 \cdot 20}

97 1^{2} - 4 \cdot 20 \cdot 0 = 971

x_{1, 2} = \frac{- 971 \pm 971}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 971 + 971}{2 \cdot 20}, x_{2} = \frac{- 971 - 971}{2 \cdot 20}

x = \frac{- 971 + 971}{2 \cdot 20} : 0

x = \frac{- 971 - 971}{2 \cdot 20} : - \frac{971}{20}

The solutions to the quadratic equation are:

x = 0, x = - \frac{971}{20}

x^{2} - 2 (k - 1) x + 6 k - 11 = 0

a^{2} + 2 1^{2} = 2 9^{2}

6 x^{2} + 8 x - 4 = 0

π x^{2} = 500

a^{2} = \frac{1}{9}

What are the solutions to the equation ((3x)^2+(4x)^2)-4x+975x=5x^2 ?
The solutions to the equation ((3x)^2+(4x)^2)-4x+975x=5x^2 are x=0,x=-971/20
Find the zeros of ((3x)^2+(4x)^2)-4x+975x=5x^2
The zeros of ((3x)^2+(4x)^2)-4x+975x=5x^2 are x=0,x=-971/20