What are the solutions to the equation (x^2+x+10)=3 ?

The solutions to the equation (x^2+x+10)=3 are x=-1/2+i(3sqrt(3))/2 ,x=-1/2-i(3sqrt(3))/2

Find the zeros of (x^2+x+10)=3

The zeros of (x^2+x+10)=3 are x=-1/2+i(3sqrt(3))/2 ,x=-1/2-i(3sqrt(3))/2

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(x^{2} + x + 10) = 3

x = - \frac{1}{2} + i \frac{3 3}{2}, x = - \frac{1}{2} - i \frac{3 3}{2}

Solution steps

(x^{2} + x + 10) = 3

Refine

x^{2} + x + 10 = 3

Move

3

to the left side

x^{2} + x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 7 : 33 i

x_{1, 2} = \frac{- 1 \pm 3 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3 3 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 3 3 i}{2 \cdot 1}

x = \frac{- 1 + 3 3 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3 3}{2}

x = \frac{- 1 - 3 3 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3 3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{3 3}{2}, x = - \frac{1}{2} - i \frac{3 3}{2}

x, z = x^{2} - x y + y^{2}

k^{2} - 15 k = - 44

- 0.025 x^{2} - 0.5 x + 60 = 0

x (x + 7) = 60

x^{2} + 3 = \frac{7 x}{2}

What are the solutions to the equation (x^2+x+10)=3 ?
The solutions to the equation (x^2+x+10)=3 are x=-1/2+i(3sqrt(3))/2 ,x=-1/2-i(3sqrt(3))/2
Find the zeros of (x^2+x+10)=3
The zeros of (x^2+x+10)=3 are x=-1/2+i(3sqrt(3))/2 ,x=-1/2-i(3sqrt(3))/2