What are the solutions to the equation r^2+9r+14=0 ?

The solutions to the equation r^2+9r+14=0 are r=-2,r=-7

Find the zeros of r^2+9r+14=0

The zeros of r^2+9r+14=0 are r=-2,r=-7

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r^{2} + 9 r + 14 = 0

r = - 2, r = - 7

Solution steps

r^{2} + 9 r + 14 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 14 = 5

r_{1, 2} = \frac{- 9 \pm 5}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 9 + 5}{2 \cdot 1}, r_{2} = \frac{- 9 - 5}{2 \cdot 1}

r = \frac{- 9 + 5}{2 \cdot 1} : - 2

r = \frac{- 9 - 5}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

r = - 2, r = - 7

2 x^{2} + 25 = 13 x

5 y^{2} - 21 y + 18

\frac{m + 7}{m ^{2} + 4 m - 21}

∣ x ∣ - ∣ x - 1 ∣ + ∣ x + 2 ∣ \geq 0

6 \cdot 15

What are the solutions to the equation r^2+9r+14=0 ?
The solutions to the equation r^2+9r+14=0 are r=-2,r=-7
Find the zeros of r^2+9r+14=0
The zeros of r^2+9r+14=0 are r=-2,r=-7