What are the solutions to the equation y^2-300y+10000=0 ?

The solutions to the equation y^2-300y+10000=0 are y=50(3+sqrt(5)),y=50(3-sqrt(5))

Find the zeros of y^2-300y+10000=0

The zeros of y^2-300y+10000=0 are y=50(3+sqrt(5)),y=50(3-sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 300 y + 10000 = 0

y = 50 (3 + 5), y = 50 (3 - 5)

Decimal Notation

y = 261.80339 \dots, y = 38.19660 \dots

Solution steps

y^{2} - 300 y + 10000 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 300 ) \pm ( - 300 ) ^{2} - 4 \cdot 1 \cdot 10000}{2 \cdot 1}

(- 300)^{2} - 4 \cdot 1 \cdot 10000 = 1005

y_{1, 2} = \frac{- ( - 300 ) \pm 100 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 300 ) + 100 5}{2 \cdot 1}, y_{2} = \frac{- ( - 300 ) - 100 5}{2 \cdot 1}

y = \frac{- ( - 300 ) + 100 5}{2 \cdot 1} : 50 (3 + 5)

y = \frac{- ( - 300 ) - 100 5}{2 \cdot 1} : 50 (3 - 5)

The solutions to the quadratic equation are:

y = 50 (3 + 5), y = 50 (3 - 5)

(2 - x) \cdot (- 2 - x) + 1 = 0

y, m^{2} \cdot 3 y - mλ = y^{2}

r, z = 4 - r^{2}

0.5 q^{2} + 30 q - 350 = 0

(5 x - 4) 2 - (3 x + 2) (2 x - 1) = 20 x (x - 2) + 27

What are the solutions to the equation y^2-300y+10000=0 ?
The solutions to the equation y^2-300y+10000=0 are y=50(3+sqrt(5)),y=50(3-sqrt(5))
Find the zeros of y^2-300y+10000=0
The zeros of y^2-300y+10000=0 are y=50(3+sqrt(5)),y=50(3-sqrt(5))