What are the solutions to the equation quadraticformula 6x^2+5x-4=0 ?

The solutions to the equation quadraticformula 6x^2+5x-4=0 are x= 1/2 ,x=-4/3

Find the zeros of quadraticformula 6x^2+5x-4=0

The zeros of quadraticformula 6x^2+5x-4=0 are x= 1/2 ,x=-4/3

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6 x^{2} + 5 x - 4 = 0

x = \frac{1}{2}, x = - \frac{4}{3}

Decimal Notation

x = 0.5, x = - 1.33333 \dots

Solution steps

6 x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 4) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 6}, x_{2} = \frac{- 5 - 11}{2 \cdot 6}

x = \frac{- 5 + 11}{2 \cdot 6} : \frac{1}{2}

x = \frac{- 5 - 11}{2 \cdot 6} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{4}{3}

x (x - 3) + 1 = 0

x, f (x + 3) = 4 x^{2} + 3 x - 4

x, 1 - 4 x + 2 x^{2} - 2 y^{3} = 0

y, y^{2} = 2 y

5.8 \cdot 1 5^{2} + 0.32 \cdot y^{2} - 47 \cdot 15 - 2.7 y + 1750 = 145000

What are the solutions to the equation quadraticformula 6x^2+5x-4=0 ?
The solutions to the equation quadraticformula 6x^2+5x-4=0 are x= 1/2 ,x=-4/3
Find the zeros of quadraticformula 6x^2+5x-4=0
The zeros of quadraticformula 6x^2+5x-4=0 are x= 1/2 ,x=-4/3