What are the solutions to the equation 5t^2-2.8t=1.1 ?

The solutions to the equation 5t^2-2.8t=1.1 are t=(14+sqrt(746))/(50),t=(14-sqrt(746))/(50)

Find the zeros of 5t^2-2.8t=1.1

The zeros of 5t^2-2.8t=1.1 are t=(14+sqrt(746))/(50),t=(14-sqrt(746))/(50)

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5 t^{2} - 2.8 t = 1.1

t = \frac{14 + 746}{50}, t = \frac{14 - 746}{50}

Decimal Notation

t = 0.82626 \dots, t = - 0.26626 \dots

Solution steps

5 t^{2} - 2.8 t = 1.1

Multiply both sides by

10

50 t^{2} - 28 t = 11

Move

11

to the left side

50 t^{2} - 28 t - 11 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 50 ( - 11 )}{2 \cdot 50}

(- 28)^{2} - 4 \cdot 50 (- 11) = 2746

t_{1, 2} = \frac{- ( - 28 ) \pm 2 746}{2 \cdot 50}

Separate the solutions

t_{1} = \frac{- ( - 28 ) + 2 746}{2 \cdot 50}, t_{2} = \frac{- ( - 28 ) - 2 746}{2 \cdot 50}

t = \frac{- ( - 28 ) + 2 746}{2 \cdot 50} : \frac{14 + 746}{50}

t = \frac{- ( - 28 ) - 2 746}{2 \cdot 50} : \frac{14 - 746}{50}

The solutions to the quadratic equation are:

t = \frac{14 + 746}{50}, t = \frac{14 - 746}{50}

x, y = - 0.000008 x^{2} + 0.0064 x + 0.2547

2 x^{2} + 4 = 8

x, z = x^{2} y + y^{2}

3 x^{2} + 14 = 89

2 x^{2} - 5 x = x^{2} - 6 x + 2

What are the solutions to the equation 5t^2-2.8t=1.1 ?
The solutions to the equation 5t^2-2.8t=1.1 are t=(14+sqrt(746))/(50),t=(14-sqrt(746))/(50)
Find the zeros of 5t^2-2.8t=1.1
The zeros of 5t^2-2.8t=1.1 are t=(14+sqrt(746))/(50),t=(14-sqrt(746))/(50)