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What are the solutions to the equation (3)^2+y^2=49 ?
The solutions to the equation (3)^2+y^2=49 are y=2sqrt(10),y=-2sqrt(10)Find the zeros of (3)^2+y^2=49
The zeros of (3)^2+y^2=49 are y=2sqrt(10),y=-2sqrt(10)