What are the solutions to the equation (3w-5)w=28 ?

The solutions to the equation (3w-5)w=28 are w=4,w=-7/3

Find the zeros of (3w-5)w=28

The zeros of (3w-5)w=28 are w=4,w=-7/3

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(3 w - 5) w = 28

w = 4, w = - \frac{7}{3}

Decimal Notation

w = 4, w = - 2.33333 \dots

Solution steps

(3 w - 5) w = 28

Expand

(3 w - 5) w : 3 w^{2} - 5 w

3 w^{2} - 5 w = 28

Move

28

to the left side

3 w^{2} - 5 w - 28 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 28 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 28) = 19

w_{1, 2} = \frac{- ( - 5 ) \pm 19}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 19}{2 \cdot 3}, w_{2} = \frac{- ( - 5 ) - 19}{2 \cdot 3}

w = \frac{- ( - 5 ) + 19}{2 \cdot 3} : 4

w = \frac{- ( - 5 ) - 19}{2 \cdot 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

w = 4, w = - \frac{7}{3}

t^{2} + 2 t + 6 = 7 t + 2

x^{2} - 16 x - 36 = 0

k^{2} - 2 k = - 2

0.75 \frac{π d ^{2}}{4} = 6573.35

\frac{1}{2} + x \cdot x = \frac{4}{3}

What are the solutions to the equation (3w-5)w=28 ?
The solutions to the equation (3w-5)w=28 are w=4,w=-7/3
Find the zeros of (3w-5)w=28
The zeros of (3w-5)w=28 are w=4,w=-7/3