What are the solutions to the equation k^2+8k+12=0 ?

The solutions to the equation k^2+8k+12=0 are k=-2,k=-6

Find the zeros of k^2+8k+12=0

The zeros of k^2+8k+12=0 are k=-2,k=-6

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k^{2} + 8 k + 12 = 0

k = - 2, k = - 6

Solution steps

k^{2} + 8 k + 12 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 12 = 4

k_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 8 + 4}{2 \cdot 1}, k_{2} = \frac{- 8 - 4}{2 \cdot 1}

k = \frac{- 8 + 4}{2 \cdot 1} : - 2

k = \frac{- 8 - 4}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

k = - 2, k = - 6

2 x + 6 \geq 9 x - 1

2 - 5 x + 6 = 0

\frac{3}{4} \cdot \frac{4}{3}

v^{2} = - 144

2 (x - 3)^{2} + (x + 1)^{2} = 11 x + 1

What are the solutions to the equation k^2+8k+12=0 ?
The solutions to the equation k^2+8k+12=0 are k=-2,k=-6
Find the zeros of k^2+8k+12=0
The zeros of k^2+8k+12=0 are k=-2,k=-6