What are the solutions to the equation 12^2=9^2+b^2 ?

The solutions to the equation 12^2=9^2+b^2 are b=3sqrt(7),b=-3sqrt(7)

Find the zeros of 12^2=9^2+b^2

The zeros of 12^2=9^2+b^2 are b=3sqrt(7),b=-3sqrt(7)

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1 2^{2} = 9^{2} + b^{2}

b = 37, b = - 37

Decimal Notation

b = 7.93725 \dots, b = - 7.93725 \dots

Solution steps

1 2^{2} = 9^{2} + b^{2}

Switch sides

9^{2} + b^{2} = 1 2^{2}

Move

9^{2}

to the right side

b^{2} = 63

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 63, b = - 63

63 = 37

- 63 = - 37

b = 37, b = - 37

x^{2} - 49 = 0

9 w^{2} + 25 = 30 w

x^{2} - 8 x = 84

X^{2} + 4 X - 5 = 0

x^{2} = 302

What are the solutions to the equation 12^2=9^2+b^2 ?
The solutions to the equation 12^2=9^2+b^2 are b=3sqrt(7),b=-3sqrt(7)
Find the zeros of 12^2=9^2+b^2
The zeros of 12^2=9^2+b^2 are b=3sqrt(7),b=-3sqrt(7)