What are the solutions to the equation -5(2x-10)(10+5x)=0 ?

The solutions to the equation -5(2x-10)(10+5x)=0 are x=5,x=-2

Find the zeros of -5(2x-10)(10+5x)=0

The zeros of -5(2x-10)(10+5x)=0 are x=5,x=-2

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- 5 (2 x - 10) (10 + 5 x) = 0

x = 5, x = - 2

Solution steps

- 5 (2 x - 10) (10 + 5 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 10 = 0 or 10 + 5 x = 0

Solve

2 x - 10 = 0 : x = 5

Solve

10 + 5 x = 0 : x = - 2

The solutions to the quadratic equation are:

x = 5, x = - 2

0 = - \frac{1}{4} x^{2} + 4 x - 1

2 x - 3 = 1 - 2 x + x^{2}

- 10 x^{2} + 1760 x - 5000 = 72440

4 x^{2} - x - 9 = - x - 8

- 0.0006 t^{2} + 0.048 t - 0.29 = 0

What are the solutions to the equation -5(2x-10)(10+5x)=0 ?
The solutions to the equation -5(2x-10)(10+5x)=0 are x=5,x=-2
Find the zeros of -5(2x-10)(10+5x)=0
The zeros of -5(2x-10)(10+5x)=0 are x=5,x=-2