What are the solutions to the equation 3x^2-12x=-2 ?

The solutions to the equation 3x^2-12x=-2 are x=(6+sqrt(30))/3 ,x=(6-sqrt(30))/3

Find the zeros of 3x^2-12x=-2

The zeros of 3x^2-12x=-2 are x=(6+sqrt(30))/3 ,x=(6-sqrt(30))/3

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3 x^{2} - 12 x = - 2

x = \frac{6 + 30}{3}, x = \frac{6 - 30}{3}

Decimal Notation

x = 3.82574 \dots, x = 0.17425 \dots

Solution steps

3 x^{2} - 12 x = - 2

Move

2

to the left side

3 x^{2} - 12 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 2 = 230

x_{1, 2} = \frac{- ( - 12 ) \pm 2 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 30}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 2 30}{2 \cdot 3}

x = \frac{- ( - 12 ) + 2 30}{2 \cdot 3} : \frac{6 + 30}{3}

x = \frac{- ( - 12 ) - 2 30}{2 \cdot 3} : \frac{6 - 30}{3}

The solutions to the quadratic equation are:

x = \frac{6 + 30}{3}, x = \frac{6 - 30}{3}

- 2 (x - 3)^{2} + 4 = 0

31 x + 5 x^{2} = - 662

6 t^{2} - t - 15 = 0

2 x^{2} + 1 x + 1 = 0

x^{2} = 961

What are the solutions to the equation 3x^2-12x=-2 ?
The solutions to the equation 3x^2-12x=-2 are x=(6+sqrt(30))/3 ,x=(6-sqrt(30))/3
Find the zeros of 3x^2-12x=-2
The zeros of 3x^2-12x=-2 are x=(6+sqrt(30))/3 ,x=(6-sqrt(30))/3