What are the solutions to the equation x^2+5x+13=1 ?

The solutions to the equation x^2+5x+13=1 are x=-5/2+i(sqrt(23))/2 ,x=-5/2-i(sqrt(23))/2

Find the zeros of x^2+5x+13=1

The zeros of x^2+5x+13=1 are x=-5/2+i(sqrt(23))/2 ,x=-5/2-i(sqrt(23))/2

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x^{2} + 5 x + 13 = 1

x = - \frac{5}{2} + i \frac{23}{2}, x = - \frac{5}{2} - i \frac{23}{2}

Solution steps

x^{2} + 5 x + 13 = 1

Move

1

to the left side

x^{2} + 5 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 12 : 23 i

x_{1, 2} = \frac{- 5 \pm 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 23 i}{2 \cdot 1}, x_{2} = \frac{- 5 - 23 i}{2 \cdot 1}

x = \frac{- 5 + 23 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{23}{2}

x = \frac{- 5 - 23 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{23}{2}, x = - \frac{5}{2} - i \frac{23}{2}

- 5 z^{2} - 4 z + 3 = 0

- 5 x^{2} = 125

x^{2} + 16 x + 64 = 2 x^{2} - 32 + 256

y, x = 1 - (7 y - 4)^{2}

x, 15 x^{2} y + 22 x y - 6 = 0

What are the solutions to the equation x^2+5x+13=1 ?
The solutions to the equation x^2+5x+13=1 are x=-5/2+i(sqrt(23))/2 ,x=-5/2-i(sqrt(23))/2
Find the zeros of x^2+5x+13=1
The zeros of x^2+5x+13=1 are x=-5/2+i(sqrt(23))/2 ,x=-5/2-i(sqrt(23))/2