What are the solutions to the equation 31=(x+3)(x+6) ?

The solutions to the equation 31=(x+3)(x+6) are x=(-9+sqrt(133))/2 ,x=(-9-sqrt(133))/2

Find the zeros of 31=(x+3)(x+6)

The zeros of 31=(x+3)(x+6) are x=(-9+sqrt(133))/2 ,x=(-9-sqrt(133))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

31 = (x + 3) (x + 6)

x = \frac{- 9 + 133}{2}, x = \frac{- 9 - 133}{2}

Decimal Notation

x = 1.26628 \dots, x = - 10.26628 \dots

Solution steps

31 = (x + 3) (x + 6)

Expand

(x + 3) (x + 6) : x^{2} + 9 x + 18

31 = x^{2} + 9 x + 18

Switch sides

x^{2} + 9 x + 18 = 31

Move

31

to the left side

x^{2} + 9 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 13) = 133

x_{1, 2} = \frac{- 9 \pm 133}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 133}{2 \cdot 1}, x_{2} = \frac{- 9 - 133}{2 \cdot 1}

x = \frac{- 9 + 133}{2 \cdot 1} : \frac{- 9 + 133}{2}

x = \frac{- 9 - 133}{2 \cdot 1} : \frac{- 9 - 133}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 133}{2}, x = \frac{- 9 - 133}{2}

- 3 x^{2} - 12 x - 15

x \cdot x - x = 6

16 - 4 x^{2} = 0

74 x^{2} + 250 x - 600 = 0

0 = x - x^{2}

What are the solutions to the equation 31=(x+3)(x+6) ?
The solutions to the equation 31=(x+3)(x+6) are x=(-9+sqrt(133))/2 ,x=(-9-sqrt(133))/2
Find the zeros of 31=(x+3)(x+6)
The zeros of 31=(x+3)(x+6) are x=(-9+sqrt(133))/2 ,x=(-9-sqrt(133))/2