What are the solutions to the equation 6x^2-4x=-2 ?

The solutions to the equation 6x^2-4x=-2 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3

Find the zeros of 6x^2-4x=-2

The zeros of 6x^2-4x=-2 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3

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6 x^{2} - 4 x = - 2

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

Solution steps

6 x^{2} - 4 x = - 2

Move

2

to the left side

6 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

Simplify

(- 4)^{2} - 4 \cdot 6 \cdot 2 : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 6}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 6}

x = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 6} : \frac{1}{3} + i \frac{2}{3}

x = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 6} : \frac{1}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

r, V = π r^{2}

{\frac{3}{2} (p - 2)}^{2}

6^{2} + x^{2} = 100

x, x^{2} + y^{2} + z^{2} - 4 x = 0

(x + 4)^{2} = 5

What are the solutions to the equation 6x^2-4x=-2 ?
The solutions to the equation 6x^2-4x=-2 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3
Find the zeros of 6x^2-4x=-2
The zeros of 6x^2-4x=-2 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3