What is 1<|x-11/3 |+7/3 ?

The solution to 1<|x-11/3 |+7/3 is True for all x

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1<|x-11/3 |+7/3

1 < x - \frac{11}{3} + \frac{7}{3}

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

1 < x - \frac{11}{3} + \frac{7}{3}

Switch sides

x - \frac{11}{3} + \frac{7}{3} > 1

Move

\frac{7}{3}

to the right side

x - \frac{11}{3} > - \frac{4}{3}

Absolute values are always greater or equal to 0

True for all x

- 12 x^{2} y^{2} (10 x^{3} y^{2})

\frac{1}{4} (4)^{- 1}

28 x^{2} y^{4} z^{2} - 9 x z^{5}

2 x + 18 = 5 x - 6

\frac{π}{8} \cdot \frac{180}{π}