What are the solutions to the equation x^2+9x+9+8=0 ?

The solutions to the equation x^2+9x+9+8=0 are x=(-9+sqrt(13))/2 ,x=(-9-sqrt(13))/2

Find the zeros of x^2+9x+9+8=0

The zeros of x^2+9x+9+8=0 are x=(-9+sqrt(13))/2 ,x=(-9-sqrt(13))/2

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x^{2} + 9 x + 9 + 8 = 0

x = \frac{- 9 + 13}{2}, x = \frac{- 9 - 13}{2}

Decimal Notation

x = - 2.69722 \dots, x = - 6.30277 \dots

Solution steps

x^{2} + 9 x + 9 + 8 = 0

Refine

x^{2} + 9 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 17 = 13

x_{1, 2} = \frac{- 9 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 13}{2 \cdot 1}, x_{2} = \frac{- 9 - 13}{2 \cdot 1}

x = \frac{- 9 + 13}{2 \cdot 1} : \frac{- 9 + 13}{2}

x = \frac{- 9 - 13}{2 \cdot 1} : \frac{- 9 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 13}{2}, x = \frac{- 9 - 13}{2}

5 y^{2} + 10 y + 4 = 0

x^{2} + (- 2 x + c)^{2} - 10 x - 8 (- 2 x + c) + 21 = 0

- 5 y - 3 = 2 y^{2}

- 45 = 0 + 10 t + \frac{1}{2} (- 0.5) t^{2}

x^{2} - 0.57 \cdot 1 0^{- 10} + 3.8 \cdot 1 0^{- 10} \cdot x = 0

What are the solutions to the equation x^2+9x+9+8=0 ?
The solutions to the equation x^2+9x+9+8=0 are x=(-9+sqrt(13))/2 ,x=(-9-sqrt(13))/2
Find the zeros of x^2+9x+9+8=0
The zeros of x^2+9x+9+8=0 are x=(-9+sqrt(13))/2 ,x=(-9-sqrt(13))/2