What are the solutions to the equation 7v^2=-35v+168 ?

The solutions to the equation 7v^2=-35v+168 are v=3,v=-8

Find the zeros of 7v^2=-35v+168

The zeros of 7v^2=-35v+168 are v=3,v=-8

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7 v^{2} = - 35 v + 168

v = 3, v = - 8

Solution steps

7 v^{2} = - 35 v + 168

Move

168

to the left side

7 v^{2} - 168 = - 35 v

Move

35 v

to the left side

7 v^{2} - 168 + 35 v = 0

Write in the standard form

a x^{2} + b x + c = 0

7 v^{2} + 35 v - 168 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 \cdot 7 ( - 168 )}{2 \cdot 7}

3 5^{2} - 4 \cdot 7 (- 168) = 77

v_{1, 2} = \frac{- 35 \pm 77}{2 \cdot 7}

Separate the solutions

v_{1} = \frac{- 35 + 77}{2 \cdot 7}, v_{2} = \frac{- 35 - 77}{2 \cdot 7}

v = \frac{- 35 + 77}{2 \cdot 7} : 3

v = \frac{- 35 - 77}{2 \cdot 7} : - 8

The solutions to the quadratic equation are:

v = 3, v = - 8

(11 m + 2 - 4 m^{2})^{2} - 4 (m^{2} + 2) (4 m^{2} + 26 - 22 m) = 0

x, x^{2} = \frac{4 R}{3} (2 R - \frac{4 R}{3})

u^{2} - 4 u = 12

a, (a - b)^{2} = 12

x^{2} = 0.9

What are the solutions to the equation 7v^2=-35v+168 ?
The solutions to the equation 7v^2=-35v+168 are v=3,v=-8
Find the zeros of 7v^2=-35v+168
The zeros of 7v^2=-35v+168 are v=3,v=-8