What are the solutions to the equation 10x^2+4x+40=0 ?

The solutions to the equation 10x^2+4x+40=0 are x=-1/5+i(3sqrt(11))/5 ,x=-1/5-i(3sqrt(11))/5

Find the zeros of 10x^2+4x+40=0

The zeros of 10x^2+4x+40=0 are x=-1/5+i(3sqrt(11))/5 ,x=-1/5-i(3sqrt(11))/5

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10 x^{2} + 4 x + 40 = 0

x = - \frac{1}{5} + i \frac{3 11}{5}, x = - \frac{1}{5} - i \frac{3 11}{5}

Solution steps

10 x^{2} + 4 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 10 \cdot 40}{2 \cdot 10}

Simplify

4^{2} - 4 \cdot 10 \cdot 40 : 1211 i

x_{1, 2} = \frac{- 4 \pm 12 11 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 4 + 12 11 i}{2 \cdot 10}, x_{2} = \frac{- 4 - 12 11 i}{2 \cdot 10}

x = \frac{- 4 + 12 11 i}{2 \cdot 10} : - \frac{1}{5} + i \frac{3 11}{5}

x = \frac{- 4 - 12 11 i}{2 \cdot 10} : - \frac{1}{5} - i \frac{3 11}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5} + i \frac{3 11}{5}, x = - \frac{1}{5} - i \frac{3 11}{5}

y, x = 3 y^{2}

x, 2 x^{2} y - 4 y = - 24

x^{2} = 135

6 x^{2} - 32 = 262

x, x^{2} + 14 x + 24 = 0

What are the solutions to the equation 10x^2+4x+40=0 ?
The solutions to the equation 10x^2+4x+40=0 are x=-1/5+i(3sqrt(11))/5 ,x=-1/5-i(3sqrt(11))/5
Find the zeros of 10x^2+4x+40=0
The zeros of 10x^2+4x+40=0 are x=-1/5+i(3sqrt(11))/5 ,x=-1/5-i(3sqrt(11))/5