What are the solutions to the equation (3x+4)^2-25=0 ?

The solutions to the equation (3x+4)^2-25=0 are x= 1/3 ,x=-3

Find the zeros of (3x+4)^2-25=0

The zeros of (3x+4)^2-25=0 are x= 1/3 ,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 x + 4)^{2} - 25 = 0

x = \frac{1}{3}, x = - 3

Decimal Notation

x = 0.33333 \dots, x = - 3

Solution steps

(3 x + 4)^{2} - 25 = 0

Move

25

to the right side

(3 x + 4)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 4 = 25 : x = \frac{1}{3}

Solve

3 x + 4 = - 25 : x = - 3

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 3

x^{2} + 5 x + 9 = - 3 x + 29

x, f (x + 2) = (x + 2)^{2}

p, p (2 p + q) = 135

(x + x + 2)^{2} = x^{2} + (x + 2)^{2} + 336

(9 n + 1)^{2} = 9

What are the solutions to the equation (3x+4)^2-25=0 ?
The solutions to the equation (3x+4)^2-25=0 are x= 1/3 ,x=-3
Find the zeros of (3x+4)^2-25=0
The zeros of (3x+4)^2-25=0 are x= 1/3 ,x=-3