What are the solutions to the equation (3x+2)(x+3)=0 ?

The solutions to the equation (3x+2)(x+3)=0 are x=-2/3 ,x=-3

Find the zeros of (3x+2)(x+3)=0

The zeros of (3x+2)(x+3)=0 are x=-2/3 ,x=-3

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(3 x + 2) (x + 3) = 0

x = - \frac{2}{3}, x = - 3

Decimal Notation

x = - 0.66666 \dots, x = - 3

Solution steps

(3 x + 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or x + 3 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 3

x^{2} - 23.5 x - 1.75 = 0

x^{2} - 9 = 0, (- 3, - 1, 1, 3)

x^{2} + 7 x = - 8

8 x + 3 = 8 x^{2}

x \cdot 0.45 + (- \frac{x ^{2}}{2 ( - 8.5 )}) = 50

What are the solutions to the equation (3x+2)(x+3)=0 ?
The solutions to the equation (3x+2)(x+3)=0 are x=-2/3 ,x=-3
Find the zeros of (3x+2)(x+3)=0
The zeros of (3x+2)(x+3)=0 are x=-2/3 ,x=-3