What are the solutions to the equation (1)=x^2 ?

The solutions to the equation (1)=x^2 are x=1,x=-1

Find the zeros of (1)=x^2

The zeros of (1)=x^2 are x=1,x=-1

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(1) = x^{2}

x = 1, x = - 1

Solution steps

(1) = x^{2}

Switch sides

x^{2} = (1)

Remove parentheses:

(a) = a

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

2 r^{2} + 12 r + 10 = 0

(1 - 0.0038)^{5} = (1 - 0.0054)^{3} (1 + x)^{2}

- 5 x^{2} + 525 x - 13500 = 0

a, (a + b + c) (1 + ab + b c + c a) = 32

x, (\frac{- G}{2 \cdot 299.98}) \cdot x^{2} + 0.58 x = 0

What are the solutions to the equation (1)=x^2 ?
The solutions to the equation (1)=x^2 are x=1,x=-1
Find the zeros of (1)=x^2
The zeros of (1)=x^2 are x=1,x=-1