What are the solutions to the equation 4y^2-2400y+1442000=0 ?

The solutions to the equation 4y^2-2400y+1442000=0 are y=300+10sqrt(2705)i,y=300-10sqrt(2705)i

Find the zeros of 4y^2-2400y+1442000=0

The zeros of 4y^2-2400y+1442000=0 are y=300+10sqrt(2705)i,y=300-10sqrt(2705)i

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4 y^{2} - 2400 y + 1442000 = 0

y = 300 + 102705 i, y = 300 - 102705 i

Solution steps

4 y^{2} - 2400 y + 1442000 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2400 ) \pm ( - 2400 ) ^{2} - 4 \cdot 4 \cdot 1442000}{2 \cdot 4}

Simplify

(- 2400)^{2} - 4 \cdot 4 \cdot 1442000 : 802705 i

y_{1, 2} = \frac{- ( - 2400 ) \pm 80 2705 i}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- ( - 2400 ) + 80 2705 i}{2 \cdot 4}, y_{2} = \frac{- ( - 2400 ) - 80 2705 i}{2 \cdot 4}

y = \frac{- ( - 2400 ) + 80 2705 i}{2 \cdot 4} : 300 + 102705 i

y = \frac{- ( - 2400 ) - 80 2705 i}{2 \cdot 4} : 300 - 102705 i

The solutions to the quadratic equation are:

y = 300 + 102705 i, y = 300 - 102705 i

25 x^{2} - 30 x = 0

2 x^{2} - 6 x + 7

4 v^{2} - 4 = 15 v

5 x^{2} - 25 x = - 20

4 x^{2} + 25 x + 6 = 0

What are the solutions to the equation 4y^2-2400y+1442000=0 ?
The solutions to the equation 4y^2-2400y+1442000=0 are y=300+10sqrt(2705)i,y=300-10sqrt(2705)i
Find the zeros of 4y^2-2400y+1442000=0
The zeros of 4y^2-2400y+1442000=0 are y=300+10sqrt(2705)i,y=300-10sqrt(2705)i