What are the solutions to the equation (x)=x^2-x+10 ?

The solutions to the equation (x)=x^2-x+10 are x=1+3i,x=1-3i

Find the zeros of (x)=x^2-x+10

The zeros of (x)=x^2-x+10 are x=1+3i,x=1-3i

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(x) = x^{2} - x + 10

x = 1 + 3 i, x = 1 - 3 i

Solution steps

(x) = x^{2} - x + 10

Refine

x = x^{2} - x + 10

Switch sides

x^{2} - x + 10 = x

Move

x

to the left side

x^{2} - 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 10 : 6 i

x_{1, 2} = \frac{- ( - 2 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6 i}{2 \cdot 1} : 1 + 3 i

x = \frac{- ( - 2 ) - 6 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

x^{2} + (- \frac{12}{13})^{2} = 1

x, - x^{2} - y^{2} + z^{2} = 1

1000000 = 100000 + 1200 x + 200 x^{2}

x, x^{2} + y^{2} - 2 x + 2 = 0

k^{2} + 16 k - 17 = 0

What are the solutions to the equation (x)=x^2-x+10 ?
The solutions to the equation (x)=x^2-x+10 are x=1+3i,x=1-3i
Find the zeros of (x)=x^2-x+10
The zeros of (x)=x^2-x+10 are x=1+3i,x=1-3i