What are the solutions to the equation p^2-7p+3=0 ?

The solutions to the equation p^2-7p+3=0 are p=(7+sqrt(37))/2 ,p=(7-sqrt(37))/2

Find the zeros of p^2-7p+3=0

The zeros of p^2-7p+3=0 are p=(7+sqrt(37))/2 ,p=(7-sqrt(37))/2

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p^{2} - 7 p + 3 = 0

p = \frac{7 + 37}{2}, p = \frac{7 - 37}{2}

Decimal Notation

p = 6.54138 \dots, p = 0.45861 \dots

Solution steps

p^{2} - 7 p + 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 3 = 37

p_{1, 2} = \frac{- ( - 7 ) \pm 37}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 7 ) + 37}{2 \cdot 1}, p_{2} = \frac{- ( - 7 ) - 37}{2 \cdot 1}

p = \frac{- ( - 7 ) + 37}{2 \cdot 1} : \frac{7 + 37}{2}

p = \frac{- ( - 7 ) - 37}{2 \cdot 1} : \frac{7 - 37}{2}

The solutions to the quadratic equation are:

p = \frac{7 + 37}{2}, p = \frac{7 - 37}{2}

\frac{5 x + 10}{x - 1} < 0

3 x = 1

a^{5} - 1

- 6 x + 9 \leq 25

12 - 8 x

What are the solutions to the equation p^2-7p+3=0 ?
The solutions to the equation p^2-7p+3=0 are p=(7+sqrt(37))/2 ,p=(7-sqrt(37))/2
Find the zeros of p^2-7p+3=0
The zeros of p^2-7p+3=0 are p=(7+sqrt(37))/2 ,p=(7-sqrt(37))/2