What are the solutions to the equation x^2=6^2+4^2 ?

The solutions to the equation x^2=6^2+4^2 are x=2sqrt(13),x=-2sqrt(13)

Find the zeros of x^2=6^2+4^2

The zeros of x^2=6^2+4^2 are x=2sqrt(13),x=-2sqrt(13)

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x^{2} = 6^{2} + 4^{2}

x = 213, x = - 213

Decimal Notation

x = 7.21110 \dots, x = - 7.21110 \dots

Solution steps

x^{2} = 6^{2} + 4^{2}

Simplify

6^{2} + 4^{2} : 52

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 52, x = - 52

52 = 213

- 52 = - 213

x = 213, x = - 213

2.5 \cdot 1 0^{- 9} = (0.072 - x) \cdot (0.04 - x)

x, x^{2} + 2 y^{2} + 3 = 0

17 - 2 y = y^{2} - 7

b (b - 4) = 0

v, m g h = \frac{1}{2} (m + m) v^{2}

What are the solutions to the equation x^2=6^2+4^2 ?
The solutions to the equation x^2=6^2+4^2 are x=2sqrt(13),x=-2sqrt(13)
Find the zeros of x^2=6^2+4^2
The zeros of x^2=6^2+4^2 are x=2sqrt(13),x=-2sqrt(13)