What are the solutions to the equation 7396-688p+12p^2=0 ?

The solutions to the equation 7396-688p+12p^2=0 are p=43,p= 43/3

Find the zeros of 7396-688p+12p^2=0

The zeros of 7396-688p+12p^2=0 are p=43,p= 43/3

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7396 - 688 p + 12 p^{2} = 0

p = 43, p = \frac{43}{3}

Decimal Notation

p = 43, p = 14.33333 \dots

Solution steps

7396 - 688 p + 12 p^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 p^{2} - 688 p + 7396 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 688 ) \pm ( - 688 ) ^{2} - 4 \cdot 12 \cdot 7396}{2 \cdot 12}

(- 688)^{2} - 4 \cdot 12 \cdot 7396 = 344

p_{1, 2} = \frac{- ( - 688 ) \pm 344}{2 \cdot 12}

Separate the solutions

p_{1} = \frac{- ( - 688 ) + 344}{2 \cdot 12}, p_{2} = \frac{- ( - 688 ) - 344}{2 \cdot 12}

p = \frac{- ( - 688 ) + 344}{2 \cdot 12} : 43

p = \frac{- ( - 688 ) - 344}{2 \cdot 12} : \frac{43}{3}

The solutions to the quadratic equation are:

p = 43, p = \frac{43}{3}

- 3 x^{2} = 2 x + 7

- 4 x = - 2 x^{2} + 16

t, s (t) = 4.9 t^{2} + 88.2 t + C

x^{2} - 2 π x - 2 π = 0

0 = - 3 x^{2} + 13 x + 10

What are the solutions to the equation 7396-688p+12p^2=0 ?
The solutions to the equation 7396-688p+12p^2=0 are p=43,p= 43/3
Find the zeros of 7396-688p+12p^2=0
The zeros of 7396-688p+12p^2=0 are p=43,p= 43/3