What are the solutions to the equation c^2=2^2+3^2 ?

The solutions to the equation c^2=2^2+3^2 are c=sqrt(13),c=-sqrt(13)

Find the zeros of c^2=2^2+3^2

The zeros of c^2=2^2+3^2 are c=sqrt(13),c=-sqrt(13)

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c^{2} = 2^{2} + 3^{2}

c = 13, c = - 13

Decimal Notation

c = 3.60555 \dots, c = - 3.60555 \dots

Solution steps

c^{2} = 2^{2} + 3^{2}

Simplify

2^{2} + 3^{2} : 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 13, c = - 13

x, (\frac{5}{4} x y + y - 1) (3 x + 2) = 2 y - 3 x - \frac{1}{2}

x^{2} + 2 = 9

x^{2} + 2 = 4

b^{2} = 2 b^{2} - 64

x (7 x - 6) = 13

What are the solutions to the equation c^2=2^2+3^2 ?
The solutions to the equation c^2=2^2+3^2 are c=sqrt(13),c=-sqrt(13)
Find the zeros of c^2=2^2+3^2
The zeros of c^2=2^2+3^2 are c=sqrt(13),c=-sqrt(13)