What are the solutions to the equation 6v^2+9=-60 ?

The solutions to the equation 6v^2+9=-60 are v=sqrt(23/2)i,v=-sqrt(23/2)i

Find the zeros of 6v^2+9=-60

The zeros of 6v^2+9=-60 are v=sqrt(23/2)i,v=-sqrt(23/2)i

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6 v^{2} + 9 = - 60

v = \frac{23}{2} i, v = - \frac{23}{2} i

Solution steps

6 v^{2} + 9 = - 60

Move

9

to the right side

6 v^{2} = - 69

Divide both sides by

6

v^{2} = - \frac{23}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = - \frac{23}{2}, v = - - \frac{23}{2}

- \frac{23}{2} = \frac{23}{2} i

- - \frac{23}{2} = - \frac{23}{2} i

v = \frac{23}{2} i, v = - \frac{23}{2} i

\frac{- 1}{2} x^{2} + \frac{11}{4} x + \frac{3}{2} = 0

x^{2} + 14 x = - 36

63.9 = 21.3 (t^{2} + 2)

x^{2} - 8 x + 3 = 0

5 x^{2} - 25 x = 125

What are the solutions to the equation 6v^2+9=-60 ?
The solutions to the equation 6v^2+9=-60 are v=sqrt(23/2)i,v=-sqrt(23/2)i
Find the zeros of 6v^2+9=-60
The zeros of 6v^2+9=-60 are v=sqrt(23/2)i,v=-sqrt(23/2)i