What are the solutions to the equation 3s^2+40s+64=0 ?

The solutions to the equation 3s^2+40s+64=0 are s=(4(sqrt(13)-5))/3 ,s=-(4(5+sqrt(13)))/3

Find the zeros of 3s^2+40s+64=0

The zeros of 3s^2+40s+64=0 are s=(4(sqrt(13)-5))/3 ,s=-(4(5+sqrt(13)))/3

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3 s^{2} + 40 s + 64 = 0

s = \frac{4 ( 13 - 5 )}{3}, s = - \frac{4 ( 5 + 13 )}{3}

Decimal Notation

s = - 1.85926 \dots, s = - 11.47406 \dots

Solution steps

3 s^{2} + 40 s + 64 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 3 \cdot 64}{2 \cdot 3}

4 0^{2} - 4 \cdot 3 \cdot 64 = 813

s_{1, 2} = \frac{- 40 \pm 8 13}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- 40 + 8 13}{2 \cdot 3}, s_{2} = \frac{- 40 - 8 13}{2 \cdot 3}

s = \frac{- 40 + 8 13}{2 \cdot 3} : \frac{4 ( 13 - 5 )}{3}

s = \frac{- 40 - 8 13}{2 \cdot 3} : - \frac{4 ( 5 + 13 )}{3}

The solutions to the quadratic equation are:

s = \frac{4 ( 13 - 5 )}{3}, s = - \frac{4 ( 5 + 13 )}{3}

2 x^{2} + 15 x - 192 = 0

16 x^{2} - 80 x + 64 = 0

(x - 5)^{2} = (x + 5)^{2} - 3 x^{2} - 25

4 x^{2} = 28 x - 49

3 m^{2} - 9 m - 11 = 0

What are the solutions to the equation 3s^2+40s+64=0 ?
The solutions to the equation 3s^2+40s+64=0 are s=(4(sqrt(13)-5))/3 ,s=-(4(5+sqrt(13)))/3
Find the zeros of 3s^2+40s+64=0
The zeros of 3s^2+40s+64=0 are s=(4(sqrt(13)-5))/3 ,s=-(4(5+sqrt(13)))/3