What are the solutions to the equation x^2+(x+5)^2+(x+8)^2=418 ?

The solutions to the equation x^2+(x+5)^2+(x+8)^2=418 are x=7,x=-47/3

Find the zeros of x^2+(x+5)^2+(x+8)^2=418

The zeros of x^2+(x+5)^2+(x+8)^2=418 are x=7,x=-47/3

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x^{2} + (x + 5)^{2} + (x + 8)^{2} = 418

x = 7, x = - \frac{47}{3}

Decimal Notation

x = 7, x = - 15.66666 \dots

Solution steps

x^{2} + (x + 5)^{2} + (x + 8)^{2} = 418

Expand

x^{2} + (x + 5)^{2} + (x + 8)^{2} : 3 x^{2} + 26 x + 89

3 x^{2} + 26 x + 89 = 418

Move

418

to the left side

3 x^{2} + 26 x - 329 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 3 ( - 329 )}{2 \cdot 3}

2 6^{2} - 4 \cdot 3 (- 329) = 68

x_{1, 2} = \frac{- 26 \pm 68}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 26 + 68}{2 \cdot 3}, x_{2} = \frac{- 26 - 68}{2 \cdot 3}

x = \frac{- 26 + 68}{2 \cdot 3} : 7

x = \frac{- 26 - 68}{2 \cdot 3} : - \frac{47}{3}

The solutions to the quadratic equation are:

x = 7, x = - \frac{47}{3}

3 (x + 1) - x (x - 1) = 4 x

A (x) = x^{2} + π \frac{( 10 - x ) ^{2}}{4}

x, x^{2} y - y - x^{2} = 0

7 x^{2} - 7 x + 1 = 0

4 u^{2} + 24 u + 4 = 0

What are the solutions to the equation x^2+(x+5)^2+(x+8)^2=418 ?
The solutions to the equation x^2+(x+5)^2+(x+8)^2=418 are x=7,x=-47/3
Find the zeros of x^2+(x+5)^2+(x+8)^2=418
The zeros of x^2+(x+5)^2+(x+8)^2=418 are x=7,x=-47/3